12x^2+36x-216=0

Solution for 12x^2+36x-216=0 equation:

12x^2+36x-216=0

a = 12; b = 36; c = -216;
Δ = b2-4ac
Δ = 362-4·12·(-216)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11664}=108$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-108}{2*12}=\frac{-144}{24}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+108}{2*12}=\frac{72}{24}
=3
$